Solve for x (7x)/9>-14/3

$\frac{7 x}{9} > - \frac{14}{3}$

Step 1

Multiply both sides by $9$ .

$\frac{7 x}{9} \cdot 9 > - \frac{14}{3} \cdot 9$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{7 x}{9} \cdot 9 > - \frac{14}{3} \cdot 9$

Rewrite the expression.

$7 x > - \frac{14}{3} \cdot 9$

Simplify the right side.

Simplify $- \frac{14}{3} \cdot 9$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{14}{3}$ into the numerator.

$7 x > \frac{- 14}{3} \cdot 9$

Factor $3$ out of $9$ .

$7 x > \frac{- 14}{3} \cdot (3 (3))$

Cancel the common factor.

$7 x > \frac{- 14}{3} \cdot (3 \cdot 3)$

Rewrite the expression.

$7 x > - 14 \cdot 3$

Multiply $- 14$ by $3$ .

$7 x > - 42$

Step 3

Divide each term in $7 x > - 42$ by $7$ and simplify.

Divide each term in $7 x > - 42$ by $7$ .

$\frac{7 x}{7} > \frac{- 42}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} > \frac{- 42}{7}$

Divide $x$ by $1$ .

$x > \frac{- 42}{7}$

Simplify the right side.

Divide $- 42$ by $7$ .

$x > - 6$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > - 6$

Interval Notation:

$(- 6, \infty)$