Solve for x -7x+x^2+6=-6x+3+x^2

$- 7 x + x^{2} + 6 = - 6 x + 3 + x^{2}$

Step 1

Move all terms containing $x$ to the left side of the equation.

Add $6 x$ to both sides of the equation.

$- 7 x + x^{2} + 6 + 6 x = 3 + x^{2}$

Subtract $x^{2}$ from both sides of the equation.

$- 7 x + x^{2} + 6 + 6 x - x^{2} = 3$

Combine the opposite terms in $- 7 x + x^{2} + 6 + 6 x - x^{2}$ .

Subtract $x^{2}$ from $x^{2}$ .

$- 7 x + 6 + 6 x + 0 = 3$

Add $- 7 x + 6 + 6 x$ and $0$ .

$- 7 x + 6 + 6 x = 3$

Add $- 7 x$ and $6 x$ .

$- x + 6 = 3$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$- x = 3 - 6$

Subtract $6$ from $3$ .

$- x = - 3$

Step 3

Divide each term in $- x = - 3$ by $- 1$ and simplify.

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x = 3$