Solve for x 8>=3+x

$8 \geq 3 + x$

Step 1

Rewrite so $x$ is on the left side of the inequality.

$3 + x \leq 8$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$x \leq 8 - 3$

Subtract $3$ from $8$ .

$x \leq 5$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \leq 5$

Interval Notation:

$(- \infty, 5]$