Solve for x 8(4-2x)=4(3-5x)+4x

$8 (4 - 2 x) = 4 (3 - 5 x) + 4 x$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 (3 - 5 x) + 4 x = 8 (4 - 2 x)$

Step 2

Simplify $4 (3 - 5 x) + 4 x$ .

Simplify each term.

Apply the distributive property.

$4 \cdot 3 + 4 (- 5 x) + 4 x = 8 (4 - 2 x)$

Multiply $4$ by $3$ .

$12 + 4 (- 5 x) + 4 x = 8 (4 - 2 x)$

Multiply $- 5$ by $4$ .

$12 - 20 x + 4 x = 8 (4 - 2 x)$

Add $- 20 x$ and $4 x$ .

$12 - 16 x = 8 (4 - 2 x)$

Step 3

Simplify $8 (4 - 2 x)$ .

Apply the distributive property.

$12 - 16 x = 8 \cdot 4 + 8 (- 2 x)$

Multiply.

Multiply $8$ by $4$ .

$12 - 16 x = 32 + 8 (- 2 x)$

Multiply $- 2$ by $8$ .

$12 - 16 x = 32 - 16 x$

Step 4

Move all terms containing $x$ to the left side of the equation.

Add $16 x$ to both sides of the equation.

$12 - 16 x + 16 x = 32$

Combine the opposite terms in $12 - 16 x + 16 x$ .

Add $- 16 x$ and $16 x$ .

$12 + 0 = 32$

Add $12$ and $0$ .

$12 = 32$

Step 5

Since $12 \neq 32$ , there are no solutions.

No solution