Solve for x (8(x+4))/6=1/3

$\frac{8 (x + 4)}{6} = \frac{1}{3}$

Step 1

Cancel the common factor of $8$ and $6$ .

Factor $2$ out of $8 (x + 4)$ .

$\frac{2 (4 (x + 4))}{6} = \frac{1}{3}$

Cancel the common factors.

Factor $2$ out of $6$ .

$\frac{2 (4 (x + 4))}{2 (3)} = \frac{1}{3}$

Cancel the common factor.

$\frac{2 (4 (x + 4))}{2 \cdot 3} = \frac{1}{3}$

Rewrite the expression.

$\frac{4 (x + 4)}{3} = \frac{1}{3}$

Step 2

Multiply both sides by $3$ .

$\frac{4 (x + 4)}{3} \cdot 3 = \frac{1}{3} \cdot 3$

Step 3

Simplify.

Simplify the left side.

Simplify $\frac{4 (x + 4)}{3} \cdot 3$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{4 (x + 4)}{3} \cdot 3 = \frac{1}{3} \cdot 3$

Rewrite the expression.

$4 (x + 4) = \frac{1}{3} \cdot 3$

Apply the distributive property.

$4 x + 4 \cdot 4 = \frac{1}{3} \cdot 3$

Multiply $4$ by $4$ .

$4 x + 16 = \frac{1}{3} \cdot 3$

Simplify the right side.

Cancel the common factor of $3$ .

Cancel the common factor.

$4 x + 16 = \frac{1}{3} \cdot 3$

Rewrite the expression.

$4 x + 16 = 1$

Step 4

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$4 x = 1 - 16$

Subtract $16$ from $1$ .

$4 x = - 15$

Divide each term in $4 x = - 15$ by $4$ and simplify.

Divide each term in $4 x = - 15$ by $4$ .

$\frac{4 x}{4} = \frac{- 15}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 15}{4}$

Divide $x$ by $1$ .

$x = \frac{- 15}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{15}{4}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{15}{4}$

Decimal Form:

$x = - 3.75$

Mixed Number Form:

$x = - 3 \frac{3}{4}$

Solve for x (8(x+4))/6=1/3

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