Solve for x 8-x/4+9=13

$8 - \frac{x}{4} + 9 = 13$

Step 1

Add $8$ and $9$ .

$- \frac{x}{4} + 17 = 13$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $17$ from both sides of the equation.

$- \frac{x}{4} = 13 - 17$

Subtract $17$ from $13$ .

$- \frac{x}{4} = - 4$

Step 3

Multiply both sides of the equation by $- 4$ .

$- 4 (- \frac{x}{4}) = - 4 \cdot - 4$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 4 (- \frac{x}{4})$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{x}{4}$ into the numerator.

$- 4 \frac{- x}{4} = - 4 \cdot - 4$

Factor $4$ out of $- 4$ .

$4 (- 1) \frac{- x}{4} = - 4 \cdot - 4$

Cancel the common factor.

$4 \cdot - 1 \frac{- x}{4} = - 4 \cdot - 4$

Rewrite the expression.

$- - x = - 4 \cdot - 4$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - 4 \cdot - 4$

Multiply $x$ by $1$ .

$x = - 4 \cdot - 4$

Simplify the right side.

Multiply $- 4$ by $- 4$ .

$x = 16$