Solve for x 8^x=7

$8^{x} = 7$

Step 1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (8^{x}) = \ln (7)$

Step 2

Expand $\ln (8^{x})$ by moving $x$ outside the logarithm.

$x \ln (8) = \ln (7)$

Step 3

Divide each term in $x \ln (8) = \ln (7)$ by $\ln (8)$ and simplify.

Divide each term in $x \ln (8) = \ln (7)$ by $\ln (8)$ .

$\frac{x \ln (8)}{\ln (8)} = \frac{\ln (7)}{\ln (8)}$

Simplify the left side.

Cancel the common factor of $\ln (8)$ .

Cancel the common factor.

$\frac{x \ln (8)}{\ln (8)} = \frac{\ln (7)}{\ln (8)}$

Divide $x$ by $1$ .

$x = \frac{\ln (7)}{\ln (8)}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{\ln (7)}{\ln (8)}$

Decimal Form:

$x = 0.93578497 \dots$