Solve for x 81-(4x)/7=21

$81 - \frac{4 x}{7} = 21$

Move all terms not containing $x$ to the right side of the equation.

Subtract $81$ from both sides of the equation.

$- \frac{4 x}{7} = 21 - 81$

Subtract $81$ from $21$ .

$- \frac{4 x}{7} = - 60$

Multiply both sides of the equation by $- \frac{7}{4}$ .

$- \frac{7}{4} (- \frac{4 x}{7}) = - \frac{7}{4} \cdot - 60$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{7}{4} (- \frac{4 x}{7})$ .

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{7}{4}$ into the numerator.

$\frac{- 7}{4} (- \frac{4 x}{7}) = - \frac{7}{4} \cdot - 60$

Move the leading negative in $- \frac{4 x}{7}$ into the numerator.

$\frac{- 7}{4} \cdot \frac{- 4 x}{7} = - \frac{7}{4} \cdot - 60$

Factor $7$ out of $- 7$ .

$\frac{7 (- 1)}{4} \cdot \frac{- 4 x}{7} = - \frac{7}{4} \cdot - 60$

Cancel the common factor.

$\frac{7 \cdot - 1}{4} \cdot \frac{- 4 x}{7} = - \frac{7}{4} \cdot - 60$

Rewrite the expression.

$\frac{- 1}{4} (- 4 x) = - \frac{7}{4} \cdot - 60$

Cancel the common factor of $4$ .

Factor $4$ out of $- 4 x$ .

$\frac{- 1}{4} (4 (- x)) = - \frac{7}{4} \cdot - 60$

Cancel the common factor.

$\frac{- 1}{4} (4 (- x)) = - \frac{7}{4} \cdot - 60$

Rewrite the expression.

$- - x = - \frac{7}{4} \cdot - 60$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{7}{4} \cdot - 60$

Multiply $x$ by $1$ .

$x = - \frac{7}{4} \cdot - 60$

Simplify the right side.

Simplify $- \frac{7}{4} \cdot - 60$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{7}{4}$ into the numerator.

$x = \frac{- 7}{4} \cdot - 60$

Factor $4$ out of $- 60$ .

$x = \frac{- 7}{4} \cdot (4 (- 15))$

Cancel the common factor.

$x = \frac{- 7}{4} \cdot (4 \cdot - 15)$

Rewrite the expression.

$x = - 7 \cdot - 15$

Multiply $- 7$ by $- 15$ .

$x = 105$

Solve for x 81-(4x)/7=21

Related Questions

Support LCMGCF.com by disabling your adblocker.