Solve for x 8x-2(x-5)=x+25

$8 x - 2 (x - 5) = x + 25$

Step 1

Simplify $8 x - 2 (x - 5)$ .

Simplify each term.

Apply the distributive property.

$8 x - 2 x - 2 \cdot - 5 = x + 25$

Multiply $- 2$ by $- 5$ .

$8 x - 2 x + 10 = x + 25$

Subtract $2 x$ from $8 x$ .

$6 x + 10 = x + 25$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$6 x + 10 - x = 25$

Subtract $x$ from $6 x$ .

$5 x + 10 = 25$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$5 x = 25 - 10$

Subtract $10$ from $25$ .

$5 x = 15$

Step 4

Divide each term in $5 x = 15$ by $5$ and simplify.

Divide each term in $5 x = 15$ by $5$ .

$\frac{5 x}{5} = \frac{15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{15}{5}$

Divide $x$ by $1$ .

$x = \frac{15}{5}$

Simplify the right side.

Divide $15$ by $5$ .

$x = 3$