Solve for x -8x+3-2x=-6x+3-4x

$- 8 x + 3 - 2 x = - 6 x + 3 - 4 x$

Step 1

Subtract $2 x$ from $- 8 x$ .

$- 10 x + 3 = - 6 x + 3 - 4 x$

Step 2

Subtract $4 x$ from $- 6 x$ .

$- 10 x + 3 = - 10 x + 3$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$- 10 x + 3 + 10 x = 3$

Combine the opposite terms in $- 10 x + 3 + 10 x$ .

Add $- 10 x$ and $10 x$ .

$0 + 3 = 3$

Add $0$ and $3$ .

$3 = 3$

Step 4

Since $3 = 3$ , the equation will always be true for any value of $x$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$