Solve for x 8x<=-32

$8 x \leq - 32$

Step 1

Divide each term in $8 x \leq - 32$ by $8$ .

$\frac{8 x}{8} \leq \frac{- 32}{8}$

Step 2

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} \leq \frac{- 32}{8}$

Divide $x$ by $1$ .

$x \leq \frac{- 32}{8}$

$x \leq \frac{- 32}{8}$

$x \leq \frac{- 32}{8}$

Step 3

Simplify the right side.

Divide $- 32$ by $8$ .

$x \leq - 4$

$x \leq - 4$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 4$

Interval Notation:

$(- \infty, - 4]$

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