Solve for x 8x+4-2(1-x)=8+10x-6

$8 x + 4 - 2 (1 - x) = 8 + 10 x - 6$

Step 1

Simplify $8 x + 4 - 2 (1 - x)$ .

Simplify each term.

Apply the distributive property.

$8 x + 4 - 2 \cdot 1 - 2 (- x) = 8 + 10 x - 6$

Multiply $- 2$ by $1$ .

$8 x + 4 - 2 - 2 (- x) = 8 + 10 x - 6$

Multiply $- 1$ by $- 2$ .

$8 x + 4 - 2 + 2 x = 8 + 10 x - 6$

Simplify by adding terms.

Add $8 x$ and $2 x$ .

$10 x + 4 - 2 = 8 + 10 x - 6$

Subtract $2$ from $4$ .

$10 x + 2 = 8 + 10 x - 6$

Step 2

Subtract $6$ from $8$ .

$10 x + 2 = 10 x + 2$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $10 x$ from both sides of the equation.

$10 x + 2 - 10 x = 2$

Combine the opposite terms in $10 x + 2 - 10 x$ .

Subtract $10 x$ from $10 x$ .

$0 + 2 = 2$

Add $0$ and $2$ .

$2 = 2$

Step 4

Since $2 = 2$ , the equation will always be true for any value of $x$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$