Solve for x 8x-4+3x=7x+x+14

$8 x - 4 + 3 x = 7 x + x + 14$

Step 1

Add $8 x$ and $3 x$ .

$11 x - 4 = 7 x + x + 14$

Step 2

Add $7 x$ and $x$ .

$11 x - 4 = 8 x + 14$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$11 x - 4 - 8 x = 14$

Subtract $8 x$ from $11 x$ .

$3 x - 4 = 14$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$3 x = 14 + 4$

Add $14$ and $4$ .

$3 x = 18$

Step 5

Divide each term in $3 x = 18$ by $3$ and simplify.

Divide each term in $3 x = 18$ by $3$ .

$\frac{3 x}{3} = \frac{18}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{18}{3}$

Divide $x$ by $1$ .

$x = \frac{18}{3}$

Simplify the right side.

Divide $18$ by $3$ .

$x = 6$