Solve for x 8x+4+4x=12x+1+3

$8 x + 4 + 4 x = 12 x + 1 + 3$

Add $8 x$ and $4 x$ .

$12 x + 4 = 12 x + 1 + 3$

Add $1$ and $3$ .

$12 x + 4 = 12 x + 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $12 x$ from both sides of the equation.

$12 x + 4 - 12 x = 4$

Combine the opposite terms in $12 x + 4 - 12 x$ .

Subtract $12 x$ from $12 x$ .

$0 + 4 = 4$

Add $0$ and $4$ .

$4 = 4$

Since $4 = 4$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$