Solve for x 8x-4x-6x-8=2x

$8 x - 4 x - 6 x - 8 = 2 x$

Step 1

Simplify $8 x - 4 x - 6 x - 8$ .

Subtract $4 x$ from $8 x$ .

$4 x - 6 x - 8 = 2 x$

Subtract $6 x$ from $4 x$ .

$- 2 x - 8 = 2 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$- 2 x - 8 - 2 x = 0$

Subtract $2 x$ from $- 2 x$ .

$- 4 x - 8 = 0$

Step 3

Add $8$ to both sides of the equation.

$- 4 x = 8$

Step 4

Divide each term in $- 4 x = 8$ by $- 4$ and simplify.

Divide each term in $- 4 x = 8$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{8}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{8}{- 4}$

Divide $x$ by $1$ .

$x = \frac{8}{- 4}$

Simplify the right side.

Divide $8$ by $- 4$ .

$x = - 2$