Solve for x -8x-5+3x=7+4x-9

$- 8 x - 5 + 3 x = 7 + 4 x - 9$

Add $- 8 x$ and $3 x$ .

$- 5 x - 5 = 7 + 4 x - 9$

Subtract $9$ from $7$ .

$- 5 x - 5 = 4 x - 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$- 5 x - 5 - 4 x = - 2$

Subtract $4 x$ from $- 5 x$ .

$- 9 x - 5 = - 2$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- 9 x = - 2 + 5$

Add $- 2$ and $5$ .

$- 9 x = 3$

Divide each term in $- 9 x = 3$ by $- 9$ and simplify.

Divide each term in $- 9 x = 3$ by $- 9$ .

$\frac{- 9 x}{- 9} = \frac{3}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 x}{- 9} = \frac{3}{- 9}$

Divide $x$ by $1$ .

$x = \frac{3}{- 9}$

Simplify the right side.

Cancel the common factor of $3$ and $- 9$ .

Factor $3$ out of $3$ .

$x = \frac{3 (1)}{- 9}$

Cancel the common factors.

Factor $3$ out of $- 9$ .

$x = \frac{3 \cdot 1}{3 \cdot - 3}$

Cancel the common factor.

$x = \frac{3 \cdot 1}{3 \cdot - 3}$

Rewrite the expression.

$x = \frac{1}{- 3}$

Move the negative in front of the fraction.

$x = - \frac{1}{3}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{3}$

Decimal Form:

$x = - 0.\overline{3}$