Solve for x 8x-(6x-9)+(3x-2)=4-(7x-8)

$8 x - (6 x - 9) + (3 x - 2) = 4 - (7 x - 8)$

Simplify $8 x - (6 x - 9) + 3 x - 2$ .

Simplify each term.

Apply the distributive property.

$8 x - (6 x) - - 9 + 3 x - 2 = 4 - (7 x - 8)$

Multiply $6$ by $- 1$ .

$8 x - 6 x - - 9 + 3 x - 2 = 4 - (7 x - 8)$

Multiply $- 1$ by $- 9$ .

$8 x - 6 x + 9 + 3 x - 2 = 4 - (7 x - 8)$

Simplify by adding terms.

Subtract $6 x$ from $8 x$ .

$2 x + 9 + 3 x - 2 = 4 - (7 x - 8)$

Add $2 x$ and $3 x$ .

$5 x + 9 - 2 = 4 - (7 x - 8)$

Subtract $2$ from $9$ .

$5 x + 7 = 4 - (7 x - 8)$

Simplify $4 - (7 x - 8)$ .

Simplify each term.

Apply the distributive property.

$5 x + 7 = 4 - (7 x) - - 8$

Multiply $7$ by $- 1$ .

$5 x + 7 = 4 - 7 x - - 8$

Multiply $- 1$ by $- 8$ .

$5 x + 7 = 4 - 7 x + 8$

Add $4$ and $8$ .

$5 x + 7 = - 7 x + 12$

Move all terms containing $x$ to the left side of the equation.

Add $7 x$ to both sides of the equation.

$5 x + 7 + 7 x = 12$

Add $5 x$ and $7 x$ .

$12 x + 7 = 12$

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$12 x = 12 - 7$

Subtract $7$ from $12$ .

$12 x = 5$

Divide each term in $12 x = 5$ by $12$ and simplify.

Divide each term in $12 x = 5$ by $12$ .

$\frac{12 x}{12} = \frac{5}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 x}{12} = \frac{5}{12}$

Divide $x$ by $1$ .

$x = \frac{5}{12}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{5}{12}$

Decimal Form:

$x = 0.41\overline{6}$

Solve for x 8x-(6x-9)+(3x-2)=4-(7x-8)

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