Solve for x 8x=x-3(10+x)

$8 x = x - 3 (10 + x)$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x - 3 (10 + x) = 8 x$

Simplify $x - 3 (10 + x)$ .

Simplify each term.

Apply the distributive property.

$x - 3 \cdot 10 - 3 x = 8 x$

Multiply $- 3$ by $10$ .

$x - 30 - 3 x = 8 x$

Subtract $3 x$ from $x$ .

$- 2 x - 30 = 8 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$- 2 x - 30 - 8 x = 0$

Subtract $8 x$ from $- 2 x$ .

$- 10 x - 30 = 0$

Add $30$ to both sides of the equation.

$- 10 x = 30$

Divide each term in $- 10 x = 30$ by $- 10$ and simplify.

Divide each term in $- 10 x = 30$ by $- 10$ .

$\frac{- 10 x}{- 10} = \frac{30}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 x}{- 10} = \frac{30}{- 10}$

Divide $x$ by $1$ .

$x = \frac{30}{- 10}$

Simplify the right side.

Divide $30$ by $- 10$ .

$x = - 3$