Solve for x 9-10x=2x+1-8x

$9 - 10 x = 2 x + 1 - 8 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 x + 1 - 8 x = 9 - 10 x$

Subtract $8 x$ from $2 x$ .

$- 6 x + 1 = 9 - 10 x$

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$- 6 x + 1 + 10 x = 9$

Add $- 6 x$ and $10 x$ .

$4 x + 1 = 9$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$4 x = 9 - 1$

Subtract $1$ from $9$ .

$4 x = 8$

Divide each term in $4 x = 8$ by $4$ and simplify.

Divide each term in $4 x = 8$ by $4$ .

$\frac{4 x}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{8}{4}$

Divide $x$ by $1$ .

$x = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$x = 2$