Solve for x -9-3(8x-3)=-1

$- 9 - 3 (8 x - 3) = - 1$

Simplify $- 9 - 3 (8 x - 3)$ .

Simplify each term.

Apply the distributive property.

$- 9 - 3 (8 x) - 3 \cdot - 3 = - 1$

Multiply $8$ by $- 3$ .

$- 9 - 24 x - 3 \cdot - 3 = - 1$

Multiply $- 3$ by $- 3$ .

$- 9 - 24 x + 9 = - 1$

Combine the opposite terms in $- 9 - 24 x + 9$ .

Add $- 9$ and $9$ .

$- 24 x + 0 = - 1$

Add $- 24 x$ and $0$ .

$- 24 x = - 1$

Divide each term in $- 24 x = - 1$ by $- 24$ and simplify.

Divide each term in $- 24 x = - 1$ by $- 24$ .

$\frac{- 24 x}{- 24} = \frac{- 1}{- 24}$

Simplify the left side.

Cancel the common factor of $- 24$ .

Cancel the common factor.

$\frac{- 24 x}{- 24} = \frac{- 1}{- 24}$

Divide $x$ by $1$ .

$x = \frac{- 1}{- 24}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{1}{24}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{24}$

Decimal Form:

$x = 0.041\overline{6}$