Solve for x 9-4(3x+1)=3(6-3x)-9

$9 - 4 (3 x + 1) = 3 (6 - 3 x) - 9$

Step 1

Simplify $9 - 4 (3 x + 1)$ .

Simplify each term.

Apply the distributive property.

$9 - 4 (3 x) - 4 \cdot 1 = 3 (6 - 3 x) - 9$

Multiply $3$ by $- 4$ .

$9 - 12 x - 4 \cdot 1 = 3 (6 - 3 x) - 9$

Multiply $- 4$ by $1$ .

$9 - 12 x - 4 = 3 (6 - 3 x) - 9$

Subtract $4$ from $9$ .

$- 12 x + 5 = 3 (6 - 3 x) - 9$

Step 2

Simplify $3 (6 - 3 x) - 9$ .

Simplify each term.

Apply the distributive property.

$- 12 x + 5 = 3 \cdot 6 + 3 (- 3 x) - 9$

Multiply $3$ by $6$ .

$- 12 x + 5 = 18 + 3 (- 3 x) - 9$

Multiply $- 3$ by $3$ .

$- 12 x + 5 = 18 - 9 x - 9$

Subtract $9$ from $18$ .

$- 12 x + 5 = - 9 x + 9$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $9 x$ to both sides of the equation.

$- 12 x + 5 + 9 x = 9$

Add $- 12 x$ and $9 x$ .

$- 3 x + 5 = 9$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 3 x = 9 - 5$

Subtract $5$ from $9$ .

$- 3 x = 4$

Step 5

Divide each term in $- 3 x = 4$ by $- 3$ and simplify.

Divide each term in $- 3 x = 4$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{4}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{4}{- 3}$

Divide $x$ by $1$ .

$x = \frac{4}{- 3}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{4}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{4}{3}$

Decimal Form:

$x = - 1.\overline{3}$

Mixed Number Form:

$x = - 1 \frac{1}{3}$

Solve for x 9-4(3x+1)=3(6-3x)-9

Related Questions

Support LCMGCF.com by disabling your adblocker.