Solve for x 9+7x=7x^2

$9 + 7 x = 7 x^{2}$

Subtract $7 x^{2}$ from both sides of the equation.

$9 + 7 x - 7 x^{2} = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = - 7$ , $b = 7$ , and $c = 9$ into the quadratic formula and solve for $x$ .

$\frac{- 7 \pm \sqrt{7^{2} - 4 \cdot (- 7 \cdot 9)}}{2 \cdot - 7}$

Simplify.

Simplify the numerator.

Raise $7$ to the power of $2$ .

$x = \frac{- 7 \pm \sqrt{49 - 4 \cdot - 7 \cdot 9}}{2 \cdot - 7}$

Multiply $- 4$ by $- 7$ .

$x = \frac{- 7 \pm \sqrt{49 + 28 \cdot 9}}{2 \cdot - 7}$

Multiply $28$ by $9$ .

$x = \frac{- 7 \pm \sqrt{49 + 252}}{2 \cdot - 7}$

Add $49$ and $252$ .

$x = \frac{- 7 \pm \sqrt{301}}{2 \cdot - 7}$

Multiply $2$ by $- 7$ .

$x = \frac{- 7 \pm \sqrt{301}}{- 14}$

Simplify $\frac{- 7 \pm \sqrt{301}}{- 14}$ .

$x = \frac{7 \pm \sqrt{301}}{14}$

The final answer is the combination of both solutions.

$x = \frac{7 + \sqrt{301}}{14}, \frac{7 - \sqrt{301}}{14}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{7 + \sqrt{301}}{14}, \frac{7 - \sqrt{301}}{14}$

Decimal Form:

$x = 1.73923939 \dots, - 0.73923939 \dots$