Solve for x 9(x+2)>9(x-3)

$9 (x + 2) > 9 (x - 3)$

Step 1

Simplify $9 (x + 2)$ .

Rewrite.

$0 + 0 + 9 (x + 2) > 9 (x - 3)$

Simplify by adding zeros.

$9 (x + 2) > 9 (x - 3)$

Apply the distributive property.

$9 x + 9 \cdot 2 > 9 (x - 3)$

Multiply $9$ by $2$ .

$9 x + 18 > 9 (x - 3)$

Step 2

Simplify $9 (x - 3)$ .

Apply the distributive property.

$9 x + 18 > 9 x + 9 \cdot - 3$

Multiply $9$ by $- 3$ .

$9 x + 18 > 9 x - 27$

Step 3

Move all terms containing $x$ to the left side of the inequality.

Subtract $9 x$ from both sides of the inequality.

$9 x + 18 - 9 x > - 27$

Combine the opposite terms in $9 x + 18 - 9 x$ .

Subtract $9 x$ from $9 x$ .

$0 + 18 > - 27$

Add $0$ and $18$ .

$18 > - 27$

Step 4

Since $18 > - 27$ , the inequality will always be true for any value of $x$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$