Solve for x 9(x-3)-8x>=-3

$9 (x - 3) - 8 x \geq - 3$

Step 1

Simplify $9 (x - 3) - 8 x$ .

Simplify each term.

Apply the distributive property.

$9 x + 9 \cdot - 3 - 8 x \geq - 3$

Multiply $9$ by $- 3$ .

$9 x - 27 - 8 x \geq - 3$

Subtract $8 x$ from $9 x$ .

$x - 27 \geq - 3$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $27$ to both sides of the inequality.

$x \geq - 3 + 27$

Add $- 3$ and $27$ .

$x \geq 24$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \geq 24$

Interval Notation:

$[24, \infty)$