Solve for x 9x+1-7x-18=3x+5

$9 x + 1 - 7 x - 18 = 3 x + 5$

Step 1

Simplify $9 x + 1 - 7 x - 18$ .

Subtract $7 x$ from $9 x$ .

$2 x + 1 - 18 = 3 x + 5$

Subtract $18$ from $1$ .

$2 x - 17 = 3 x + 5$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$2 x - 17 - 3 x = 5$

Subtract $3 x$ from $2 x$ .

$- x - 17 = 5$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $17$ to both sides of the equation.

$- x = 5 + 17$

Add $5$ and $17$ .

$- x = 22$

Step 4

Divide each term in $- x = 22$ by $- 1$ and simplify.

Divide each term in $- x = 22$ by $- 1$ .

$\frac{- x}{- 1} = \frac{22}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{22}{- 1}$

Divide $x$ by $1$ .

$x = \frac{22}{- 1}$

Simplify the right side.

Divide $22$ by $- 1$ .

$x = - 22$