Solve for x 9x+26+7x-17=2x+(-3x)+5x

$9 x + 26 + 7 x - 17 = 2 x + (- 3 x) + 5 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 x - 3 x + 5 x = 9 x + 26 + 7 x - 17$

Simplify $2 x - 3 x + 5 x$ .

Subtract $3 x$ from $2 x$ .

$- x + 5 x = 9 x + 26 + 7 x - 17$

Add $- x$ and $5 x$ .

$4 x = 9 x + 26 + 7 x - 17$

Simplify $9 x + 26 + 7 x - 17$ .

Add $9 x$ and $7 x$ .

$4 x = 16 x + 26 - 17$

Subtract $17$ from $26$ .

$4 x = 16 x + 9$

Move all terms containing $x$ to the left side of the equation.

Subtract $16 x$ from both sides of the equation.

$4 x - 16 x = 9$

Subtract $16 x$ from $4 x$ .

$- 12 x = 9$

Divide each term in $- 12 x = 9$ by $- 12$ and simplify.

Divide each term in $- 12 x = 9$ by $- 12$ .

$\frac{- 12 x}{- 12} = \frac{9}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 x}{- 12} = \frac{9}{- 12}$

Divide $x$ by $1$ .

$x = \frac{9}{- 12}$

Simplify the right side.

Cancel the common factor of $9$ and $- 12$ .

Factor $3$ out of $9$ .

$x = \frac{3 (3)}{- 12}$

Cancel the common factors.

Factor $3$ out of $- 12$ .

$x = \frac{3 \cdot 3}{3 \cdot - 4}$

Cancel the common factor.

$x = \frac{3 \cdot 3}{3 \cdot - 4}$

Rewrite the expression.

$x = \frac{3}{- 4}$

Move the negative in front of the fraction.

$x = - \frac{3}{4}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{3}{4}$

Decimal Form:

$x = - 0.75$