Solve for x 9x+27=9(x+2)+9

$9 x + 27 = 9 (x + 2) + 9$

Step 1

Simplify $9 (x + 2) + 9$ .

Simplify each term.

Apply the distributive property.

$9 x + 27 = 9 x + 9 \cdot 2 + 9$

Multiply $9$ by $2$ .

$9 x + 27 = 9 x + 18 + 9$

Add $18$ and $9$ .

$9 x + 27 = 9 x + 27$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$9 x + 27 - 9 x = 27$

Combine the opposite terms in $9 x + 27 - 9 x$ .

Subtract $9 x$ from $9 x$ .

$0 + 27 = 27$

Add $0$ and $27$ .

$27 = 27$

Step 3

Since $27 = 27$ , the equation will always be true for any value of $x$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$