Solve for x 9x-3(4+x)=0

$9 x - 3 (4 + x) = 0$

Step 1

Simplify $9 x - 3 (4 + x)$ .

Simplify each term.

Apply the distributive property.

$9 x - 3 \cdot 4 - 3 x = 0$

Multiply $- 3$ by $4$ .

$9 x - 12 - 3 x = 0$

Subtract $3 x$ from $9 x$ .

$6 x - 12 = 0$

Step 2

Add $12$ to both sides of the equation.

$6 x = 12$

Step 3

Divide each term in $6 x = 12$ by $6$ and simplify.

Divide each term in $6 x = 12$ by $6$ .

$\frac{6 x}{6} = \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{12}{6}$

Divide $x$ by $1$ .

$x = \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$x = 2$