Solve for x 9x-3-8x=7-x

$9 x - 3 - 8 x = 7 - x$

Step 1

Subtract $8 x$ from $9 x$ .

$x - 3 = 7 - x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$x - 3 + x = 7$

Add $x$ and $x$ .

$2 x - 3 = 7$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2 x = 7 + 3$

Add $7$ and $3$ .

$2 x = 10$

Step 4

Divide each term in $2 x = 10$ by $2$ and simplify.

Divide each term in $2 x = 10$ by $2$ .

$\frac{2 x}{2} = \frac{10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{10}{2}$

Divide $x$ by $1$ .

$x = \frac{10}{2}$

Simplify the right side.

Divide $10$ by $2$ .

$x = 5$