Solve for x 9x+3y=12

$9 x + 3 y = 12$

Step 1

Subtract $3 y$ from both sides of the equation.

$9 x = 12 - 3 y$

Step 2

Divide each term in $9 x = 12 - 3 y$ by $9$ and simplify.

Divide each term in $9 x = 12 - 3 y$ by $9$ .

$\frac{9 x}{9} = \frac{12}{9} + \frac{- 3 y}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{12}{9} + \frac{- 3 y}{9}$

Divide $x$ by $1$ .

$x = \frac{12}{9} + \frac{- 3 y}{9}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $12$ and $9$ .

Factor $3$ out of $12$ .

$x = \frac{3 (4)}{9} + \frac{- 3 y}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$x = \frac{3 \cdot 4}{3 \cdot 3} + \frac{- 3 y}{9}$

Cancel the common factor.

$x = \frac{3 \cdot 4}{3 \cdot 3} + \frac{- 3 y}{9}$

Rewrite the expression.

$x = \frac{4}{3} + \frac{- 3 y}{9}$

Cancel the common factor of $- 3$ and $9$ .

Factor $3$ out of $- 3 y$ .

$x = \frac{4}{3} + \frac{3 (- y)}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$x = \frac{4}{3} + \frac{3 (- y)}{3 (3)}$

Cancel the common factor.

$x = \frac{4}{3} + \frac{3 (- y)}{3 \cdot 3}$

Rewrite the expression.

$x = \frac{4}{3} + \frac{- y}{3}$

Move the negative in front of the fraction.

$x = \frac{4}{3} - \frac{y}{3}$