Solve for x 9x^4=36x^2

$9 x^{4} = 36 x^{2}$

Subtract $36 x^{2}$ from both sides of the equation.

$9 x^{4} - 36 x^{2} = 0$

Factor the left side of the equation.

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$9 {(x^{2})}^{2} - 36 x^{2} = 0$

Let $u = x^{2}$ . Substitute $u$ for all occurrences of $x^{2}$ .

$9 u^{2} - 36 u = 0$

Factor $9 u$ out of $9 u^{2} - 36 u$ .

Factor $9 u$ out of $9 u^{2}$ .

$9 u (u) - 36 u = 0$

Factor $9 u$ out of $- 36 u$ .

$9 u (u) + 9 u (- 4) = 0$

Factor $9 u$ out of $9 u (u) + 9 u (- 4)$ .

$9 u (u - 4) = 0$

Replace all occurrences of $u$ with $x^{2}$ .

$9 x^{2} (x^{2} - 4) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{2} = 0$

$x^{2} - 4 = 0$

Set $x^{2}$ equal to $0$ and solve for $x$ .

Set $x^{2}$ equal to $0$ .

$x^{2} = 0$

Solve $x^{2} = 0$ for $x$ .

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{0}$

Simplify $\pm \sqrt{0}$ .

Rewrite $0$ as $0^{2}$ .

$x = \pm \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 0$

Plus or minus $0$ is $0$ .

$x = 0$

Set $x^{2} - 4$ equal to $0$ and solve for $x$ .

Set $x^{2} - 4$ equal to $0$ .

$x^{2} - 4 = 0$

Solve $x^{2} - 4 = 0$ for $x$ .

Add $4$ to both sides of the equation.

$x^{2} = 4$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{4}$

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 2$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2, - 2$

The final solution is all the values that make $9 x^{2} (x^{2} - 4) = 0$ true.

$x = 0, 2, - 2$

Solve for x 9x^4=36x^2

Related Questions

Support LCMGCF.com by disabling your adblocker.