Solve for x 9x+42=4x-13

$9 x + 42 = 4 x - 13$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$9 x + 42 - 4 x = - 13$

Subtract $4 x$ from $9 x$ .

$5 x + 42 = - 13$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $42$ from both sides of the equation.

$5 x = - 13 - 42$

Subtract $42$ from $- 13$ .

$5 x = - 55$

Step 3

Divide each term in $5 x = - 55$ by $5$ and simplify.

Divide each term in $5 x = - 55$ by $5$ .

$\frac{5 x}{5} = \frac{- 55}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 55}{5}$

Divide $x$ by $1$ .

$x = \frac{- 55}{5}$

Simplify the right side.

Divide $- 55$ by $5$ .

$x = - 11$