Solve for x 9x-5=1/4(16x+60)

$9 x - 5 = \frac{1}{4} (16 x + 60)$

Simplify $\frac{1}{4} \cdot (16 x + 60)$ .

Rewrite.

$9 x - 5 = 0 + 0 + \frac{1}{4} \cdot (16 x + 60)$

Simplify by adding zeros.

$9 x - 5 = \frac{1}{4} \cdot (16 x + 60)$

Apply the distributive property.

$9 x - 5 = \frac{1}{4} (16 x) + \frac{1}{4} \cdot 60$

Cancel the common factor of $4$ .

Factor $4$ out of $16 x$ .

$9 x - 5 = \frac{1}{4} (4 (4 x)) + \frac{1}{4} \cdot 60$

Cancel the common factor.

$9 x - 5 = \frac{1}{4} (4 (4 x)) + \frac{1}{4} \cdot 60$

Rewrite the expression.

$9 x - 5 = 4 x + \frac{1}{4} \cdot 60$

Cancel the common factor of $4$ .

Factor $4$ out of $60$ .

$9 x - 5 = 4 x + \frac{1}{4} \cdot (4 (15))$

Cancel the common factor.

$9 x - 5 = 4 x + \frac{1}{4} \cdot (4 \cdot 15)$

Rewrite the expression.

$9 x - 5 = 4 x + 15$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$9 x - 5 - 4 x = 15$

Subtract $4 x$ from $9 x$ .

$5 x - 5 = 15$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$5 x = 15 + 5$

Add $15$ and $5$ .

$5 x = 20$

Divide each term in $5 x = 20$ by $5$ and simplify.

Divide each term in $5 x = 20$ by $5$ .

$\frac{5 x}{5} = \frac{20}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{20}{5}$

Divide $x$ by $1$ .

$x = \frac{20}{5}$

Simplify the right side.

Divide $20$ by $5$ .

$x = 4$