Solve for x (9x)/5+2x=1

$\frac{9 x}{5} + 2 x = 1$

Simplify $\frac{9 x}{5} + 2 x$ .

To write $2 x$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{9 x}{5} + 2 x \cdot \frac{5}{5} = 1$

Simplify terms.

Combine $2 x$ and $\frac{5}{5}$ .

$\frac{9 x}{5} + \frac{2 x \cdot 5}{5} = 1$

Combine the numerators over the common denominator.

$\frac{9 x + 2 x \cdot 5}{5} = 1$

Simplify the numerator.

Factor $x$ out of $9 x + 2 x \cdot 5$ .

Factor $x$ out of $9 x$ .

$\frac{x \cdot 9 + 2 x \cdot 5}{5} = 1$

Factor $x$ out of $2 x \cdot 5$ .

$\frac{x \cdot 9 + x (2 \cdot 5)}{5} = 1$

Factor $x$ out of $x \cdot 9 + x (2 \cdot 5)$ .

$\frac{x (9 + 2 \cdot 5)}{5} = 1$

Multiply $2$ by $5$ .

$\frac{x (9 + 10)}{5} = 1$

Add $9$ and $10$ .

$\frac{x \cdot 19}{5} = 1$

Move $19$ to the left of $x$ .

$\frac{19 x}{5} = 1$

Multiply both sides of the equation by $\frac{5}{19}$ .

$\frac{5}{19} \cdot \frac{19 x}{5} = \frac{5}{19} \cdot 1$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{19} \cdot \frac{19 x}{5}$ .

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{19} \cdot \frac{19 x}{5} = \frac{5}{19} \cdot 1$

Rewrite the expression.

$\frac{1}{19} (19 x) = \frac{5}{19} \cdot 1$

Cancel the common factor of $19$ .

Factor $19$ out of $19 x$ .

$\frac{1}{19} (19 (x)) = \frac{5}{19} \cdot 1$

Cancel the common factor.

$\frac{1}{19} (19 x) = \frac{5}{19} \cdot 1$

Rewrite the expression.

$x = \frac{5}{19} \cdot 1$

Simplify the right side.

Multiply $\frac{5}{19}$ by $1$ .

$x = \frac{5}{19}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{5}{19}$

Decimal Form:

$x = 0.26315789 \dots$

Solve for x (9x)/5+2x=1

Related Questions

Support LCMGCF.com by disabling your adblocker.