Solve for x 9x-5=3*(x-2)+13

$9 x - 5 = 3 \cdot (x - 2) + 13$

Simplify $3 \cdot (x - 2) + 13$ .

Simplify each term.

Apply the distributive property.

$9 x - 5 = 3 x + 3 \cdot - 2 + 13$

Multiply $3$ by $- 2$ .

$9 x - 5 = 3 x - 6 + 13$

Add $- 6$ and $13$ .

$9 x - 5 = 3 x + 7$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$9 x - 5 - 3 x = 7$

Subtract $3 x$ from $9 x$ .

$6 x - 5 = 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$6 x = 7 + 5$

Add $7$ and $5$ .

$6 x = 12$

Divide each term in $6 x = 12$ by $6$ and simplify.

Divide each term in $6 x = 12$ by $6$ .

$\frac{6 x}{6} = \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{12}{6}$

Divide $x$ by $1$ .

$x = \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$x = 2$