Solve for x -ax+2b>8

$- a x + 2 b > 8$

Step 1

Subtract $2 b$ from both sides of the inequality.

$- a x > 8 - 2 b$

Step 2

Divide each term in $- a x > 8 - 2 b$ by $- 1 a$ and simplify.

Divide each term in $- a x > 8 - 2 b$ by $- 1 a$ .

$\frac{- a x}{- 1 a} > \frac{8}{- 1 a} + \frac{- 2 b}{- 1 a}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{a x}{a} > \frac{8}{- 1 a} + \frac{- 2 b}{- 1 a}$

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a x}{a} > \frac{8}{- 1 a} + \frac{- 2 b}{- 1 a}$

Divide $x$ by $1$ .

$x > \frac{8}{- 1 a} + \frac{- 2 b}{- 1 a}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x > - \frac{8}{a} + \frac{- 2 b}{- 1 a}$

Dividing two negative values results in a positive value.

$x > - \frac{8}{a} + \frac{2 b}{a}$