Solve for x cube root of x-4<=5

$\sqrt[3]{x - 4} \leq 5$

To remove the radical on the left side of the inequality, cube both sides of the inequality.

${\sqrt[3]{x - 4}}^{3} \leq 5^{3}$

Simplify each side of the inequality.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{x - 4}$ as ${(x - 4)}^{\frac{1}{3}}$ .

${({(x - 4)}^{\frac{1}{3}})}^{3} \leq 5^{3}$

Simplify the left side.

Simplify ${({(x - 4)}^{\frac{1}{3}})}^{3}$ .

Multiply the exponents in ${({(x - 4)}^{\frac{1}{3}})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 4)}^{\frac{1}{3} \cdot 3} \leq 5^{3}$

Cancel the common factor of $3$ .

Cancel the common factor.

${(x - 4)}^{\frac{1}{3} \cdot 3} \leq 5^{3}$

Rewrite the expression.

${(x - 4)}^{1} \leq 5^{3}$

Simplify.

$x - 4 \leq 5^{3}$

Simplify the right side.

Raise $5$ to the power of $3$ .

$x - 4 \leq 125$

Move all terms not containing $x$ to the right side of the inequality.

Add $4$ to both sides of the inequality.

$x \leq 125 + 4$

Add $125$ and $4$ .

$x \leq 129$

The result can be shown in multiple forms.

Inequality Form:

$x \leq 129$

Interval Notation:

$(- \infty, 129]$