Solve for x f(x-1)=2^(x-5)

$f (x - 1) = 2^{x - 5}$

Step 1

Simplify $f (x - 1)$ .

Rewrite.

$0 + 0 + f (x - 1) = 2^{x - 5}$

Simplify by multiplying through.

Apply the distributive property.

$f x + f \cdot - 1 = 2^{x - 5}$

Move $- 1$ to the left of $f$ .

$f x - 1 \cdot f = 2^{x - 5}$

Rewrite $- 1 f$ as $- f$ .

$f x - f = 2^{x - 5}$

Step 2

Subtract $2^{x - 5}$ from both sides of the equation.

$f x - f - 2^{x - 5} = 0$

Step 3

Add $f$ to both sides of the equation.

$f x - 2^{x - 5} = f$