Solve for x h=4(x+3y)+2

$h = 4 (x + 3 y) + 2$

Step 1

Rewrite the equation as $4 (x + 3 y) + 2 = h$ .

$4 (x + 3 y) + 2 = h$

Step 2

Simplify each term.

Apply the distributive property.

$4 x + 4 (3 y) + 2 = h$

Multiply $3$ by $4$ .

$4 x + 12 y + 2 = h$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $12 y$ from both sides of the equation.

$4 x + 2 = h - 12 y$

Subtract $2$ from both sides of the equation.

$4 x = h - 12 y - 2$

Step 4

Divide each term in $4 x = h - 12 y - 2$ by $4$ and simplify.

Divide each term in $4 x = h - 12 y - 2$ by $4$ .

$\frac{4 x}{4} = \frac{h}{4} + \frac{- 12 y}{4} + \frac{- 2}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{h}{4} + \frac{- 12 y}{4} + \frac{- 2}{4}$

Divide $x$ by $1$ .

$x = \frac{h}{4} + \frac{- 12 y}{4} + \frac{- 2}{4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 12$ and $4$ .

Factor $4$ out of $- 12 y$ .

$x = \frac{h}{4} + \frac{4 (- 3 y)}{4} + \frac{- 2}{4}$

Cancel the common factors.

Factor $4$ out of $4$ .

$x = \frac{h}{4} + \frac{4 (- 3 y)}{4 (1)} + \frac{- 2}{4}$

Cancel the common factor.

$x = \frac{h}{4} + \frac{4 (- 3 y)}{4 \cdot 1} + \frac{- 2}{4}$

Rewrite the expression.

$x = \frac{h}{4} + \frac{- 3 y}{1} + \frac{- 2}{4}$

Divide $- 3 y$ by $1$ .

$x = \frac{h}{4} - 3 y + \frac{- 2}{4}$

Cancel the common factor of $- 2$ and $4$ .

Factor $2$ out of $- 2$ .

$x = \frac{h}{4} - 3 y + \frac{2 (- 1)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{h}{4} - 3 y + \frac{2 \cdot - 1}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{h}{4} - 3 y + \frac{2 \cdot - 1}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{h}{4} - 3 y + \frac{- 1}{2}$

Move the negative in front of the fraction.

$x = \frac{h}{4} - 3 y - \frac{1}{2}$

Solve for x h=4(x+3y)+2

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