Solve for x h(x)=(-4x-5)(-x+5)

$h (x) = (- 4 x - 5) (- x + 5)$

Step 1

Set $(- 4 x - 5) (- x + 5)$ equal to $0$ .

$(- 4 x - 5) (- x + 5) = 0$

Step 2

Solve for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$- 4 x - 5 = 0$

$- x + 5 = 0$

Set $- 4 x - 5$ equal to $0$ and solve for $x$ .

Set $- 4 x - 5$ equal to $0$ .

$- 4 x - 5 = 0$

Solve $- 4 x - 5 = 0$ for $x$ .

Add $5$ to both sides of the equation.

$- 4 x = 5$

Divide each term in $- 4 x = 5$ by $- 4$ and simplify.

Divide each term in $- 4 x = 5$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{5}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{5}{- 4}$

Divide $x$ by $1$ .

$x = \frac{5}{- 4}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{5}{4}$

Set $- x + 5$ equal to $0$ and solve for $x$ .

Set $- x + 5$ equal to $0$ .

$- x + 5 = 0$

Solve $- x + 5 = 0$ for $x$ .

Subtract $5$ from both sides of the equation.

$- x = - 5$

Divide each term in $- x = - 5$ by $- 1$ and simplify.

Divide each term in $- x = - 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 5}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 5}{- 1}$

Simplify the right side.

Divide $- 5$ by $- 1$ .

$x = 5$

The final solution is all the values that make $(- 4 x - 5) (- x + 5) = 0$ true.

$x = - \frac{5}{4}, 5$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{5}{4}, 5$

Decimal Form:

$x = - 1.25, 5$

Mixed Number Form:

$x = - 1 \frac{1}{4}, 5$

Step 4

Solve for x h(x)=(-4x-5)(-x+5)

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