Solve for x j(x)=-4/5x+7 , j(x)=-5

$j (x) = - \frac{4}{5} x + 7$ , $j (x) = - 5$

Substitute $- 5$ for $j (x)$ .

$- 5 = - \frac{4}{5} x + 7$

Solve for $x$ .

Rewrite the equation as $- \frac{4}{5} x + 7 = - 5$ .

$- \frac{4}{5} x + 7 = - 5$

Simplify each term.

Combine $x$ and $\frac{4}{5}$ .

$- \frac{x \cdot 4}{5} + 7 = - 5$

Move $4$ to the left of $x$ .

$- \frac{4 x}{5} + 7 = - 5$

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- \frac{4 x}{5} = - 5 - 7$

Subtract $7$ from $- 5$ .

$- \frac{4 x}{5} = - 12$

Multiply both sides of the equation by $- \frac{5}{4}$ .

$- \frac{5}{4} (- \frac{4 x}{5}) = - \frac{5}{4} \cdot - 12$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{5}{4} (- \frac{4 x}{5})$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{4}$ into the numerator.

$\frac{- 5}{4} (- \frac{4 x}{5}) = - \frac{5}{4} \cdot - 12$

Move the leading negative in $- \frac{4 x}{5}$ into the numerator.

$\frac{- 5}{4} \cdot \frac{- 4 x}{5} = - \frac{5}{4} \cdot - 12$

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{4} \cdot \frac{- 4 x}{5} = - \frac{5}{4} \cdot - 12$

Cancel the common factor.

$\frac{5 \cdot - 1}{4} \cdot \frac{- 4 x}{5} = - \frac{5}{4} \cdot - 12$

Rewrite the expression.

$\frac{- 1}{4} (- 4 x) = - \frac{5}{4} \cdot - 12$

Cancel the common factor of $4$ .

Factor $4$ out of $- 4 x$ .

$\frac{- 1}{4} (4 (- x)) = - \frac{5}{4} \cdot - 12$

Cancel the common factor.

$\frac{- 1}{4} (4 (- x)) = - \frac{5}{4} \cdot - 12$

Rewrite the expression.

$- - x = - \frac{5}{4} \cdot - 12$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{5}{4} \cdot - 12$

Multiply $x$ by $1$ .

$x = - \frac{5}{4} \cdot - 12$

Simplify the right side.

Simplify $- \frac{5}{4} \cdot - 12$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{5}{4}$ into the numerator.

$x = \frac{- 5}{4} \cdot - 12$

Factor $4$ out of $- 12$ .

$x = \frac{- 5}{4} \cdot (4 (- 3))$

Cancel the common factor.

$x = \frac{- 5}{4} \cdot (4 \cdot - 3)$

Rewrite the expression.

$x = - 5 \cdot - 3$

Multiply $- 5$ by $- 3$ .

$x = 15$

Solve for x j(x)=-4/5x+7 , j(x)=-5

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