Solve for x km/3-2x=4

$\frac{km}{3} - 2 x = 4$

Step 1

Subtract $\frac{km}{3}$ from both sides of the equation.

$- 2 x = 4 - \frac{km}{3}$

Step 2

Divide each term in $- 2 x = 4 - \frac{km}{3}$ by $- 2$ and simplify.

Divide each term in $- 2 x = 4 - \frac{km}{3}$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{4}{- 2} + \frac{- \frac{km}{3}}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{4}{- 2} + \frac{- \frac{km}{3}}{- 2}$

Divide $x$ by $1$ .

$x = \frac{4}{- 2} + \frac{- \frac{km}{3}}{- 2}$

Simplify the right side.

Simplify each term.

Divide $4$ by $- 2$ .

$x = - 2 + \frac{- \frac{km}{3}}{- 2}$

Dividing two negative values results in a positive value.

$x = - 2 + \frac{\frac{km}{3}}{2}$

Step 3

Simplify each term.

Multiply the numerator by the reciprocal of the denominator.

$x = - 2 + \frac{km}{3} \cdot \frac{1}{2}$

Combine fractions.

$x = - 2 + \frac{1}{3 \cdot 2} km$

Multiply $3$ by $2$ .

$x = - 2 + \frac{1}{6} km$