Solve for x kx+3x=4

$k x + 3 x = 4$

Factor $x$ out of $k x + 3 x$ .

Factor $x$ out of $k x$ .

$x k + 3 x = 4$

Factor $x$ out of $3 x$ .

$x k + x \cdot 3 = 4$

Factor $x$ out of $x k + x \cdot 3$ .

$x (k + 3) = 4$

Divide each term in $x (k + 3) = 4$ by $k + 3$ and simplify.

Divide each term in $x (k + 3) = 4$ by $k + 3$ .

$\frac{x (k + 3)}{k + 3} = \frac{4}{k + 3}$

Simplify the left side.

Cancel the common factor of $k + 3$ .

Cancel the common factor.

$\frac{x (k + 3)}{k + 3} = \frac{4}{k + 3}$

Divide $x$ by $1$ .

$x = \frac{4}{k + 3}$