Solve for x log base 1/5 of x=-1

$\log_{\frac{1}{5}} (x) = - 1$

Rewrite $\log_{\frac{1}{5}} (x) = - 1$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

${(\frac{1}{5})}^{- 1} = x$

Solve for $x$ .

Rewrite the equation as $x = {(\frac{1}{5})}^{- 1}$ .

$x = {(\frac{1}{5})}^{- 1}$

Change the sign of the exponent by rewriting the base as its reciprocal.

$x = 5$

Solve for x log base 1/5 of x=-1

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