Solve for x log base 2 of x-4=6

$\log_{2} (x - 4) = 6$

Rewrite $\log_{2} (x - 4) = 6$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$2^{6} = x - 4$

Solve for $x$ .

Rewrite the equation as $x - 4 = 2^{6}$ .

$x - 4 = 2^{6}$

Raise $2$ to the power of $6$ .

$x - 4 = 64$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$x = 64 + 4$

Add $64$ and $4$ .

$x = 68$

Solve for x log base 2 of x-4=6

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