Solve for x log base 2 of x-5=4

$\log_{2} (x - 5) = 4$

Step 1

Rewrite $\log_{2} (x - 5) = 4$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$2^{4} = x - 5$

Step 2

Solve for $x$ .

Rewrite the equation as $x - 5 = 2^{4}$ .

$x - 5 = 2^{4}$

Raise $2$ to the power of $4$ .

$x - 5 = 16$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$x = 16 + 5$

Add $16$ and $5$ .

$x = 21$

Solve for x log base 2 of x-5=4

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