Solve for x log base 2 of x+8=4

$\log_{2} (x + 8) = 4$

Step 1

Rewrite $\log_{2} (x + 8) = 4$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$2^{4} = x + 8$

Step 2

Solve for $x$ .

Rewrite the equation as $x + 8 = 2^{4}$ .

$x + 8 = 2^{4}$

Raise $2$ to the power of $4$ .

$x + 8 = 16$

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$x = 16 - 8$

Subtract $8$ from $16$ .

$x = 8$

Solve for x log base 2 of x+8=4

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