Solve for x log base 3 of x-5=2

$\log_{3} (x - 5) = 2$

Rewrite $\log_{3} (x - 5) = 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$3^{2} = x - 5$

Solve for $x$ .

Rewrite the equation as $x - 5 = 3^{2}$ .

$x - 5 = 3^{2}$

Raise $3$ to the power of $2$ .

$x - 5 = 9$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$x = 9 + 5$

Add $9$ and $5$ .

$x = 14$

Solve for x log base 3 of x-5=2

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