Solve for x log base 5 of x=-2

$\log_{5} (x) = - 2$

Rewrite $\log_{5} (x) = - 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$5^{- 2} = x$

Solve for $x$ .

Rewrite the equation as $x = 5^{- 2}$ .

$x = 5^{- 2}$

Simplify $5^{- 2}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x = \frac{1}{5^{2}}$

Raise $5$ to the power of $2$ .

$x = \frac{1}{25}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{25}$

Decimal Form:

$x = 0.04$

Solve for x log base 5 of x=-2

Related Questions

Support LCMGCF.com by disabling your adblocker.