Solve for x log base 8 of x = log base 8 of 10^-1

$\log_{8} (x) = \log_{8} (10^{- 1})$

Step 1

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$x = 10^{- 1}$

Step 2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x = \frac{1}{10}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{10}$

Decimal Form:

$x = 0.1$